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Exam Code: CPC-SEN
Exam Name: CyberArk Sentry - Privilege Cloud
Vendor: CyberArk

60 Questions & Answers
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NEW QUESTION: 1
Scenario








A. Option B
B. Option C
C. Option D
D. Option A
Answer: D
Explanation:
Using the "show ip int brief command" on R5 we can see the IP addresses assigned to this router. Then, using the "show ip route" command on R1 we can see that to reach 10.5.5.5 and 10.5.5.55 the preferred path is via Serial 1/3, which we see from the diagram is the link to R2.


NEW QUESTION: 2
Which two features improve BGP convergence? (Choose two.)
A. next-hop address tracking
B. additional paths
C. communities
D. soft reconfiguration
E. advertise map
Answer: A,B
Explanation:
The BGP Support for Next-Hop Address Tracking feature is enabled by default when a supporting Cisco software image
is installed. BGP next-hop address tracking is event driven. BGP prefixes are automatically tracked as peering sessions
are established. Next-hop changes are rapidly reported to the BGP routing process as they are updated in the RIB. This
optimization improves overall BGP convergence by reducing the response time to next-hop changes for routes
installed in the RIB. When a best path calculation is run in between BGP scanner cycles, only next-hop changes are
tracked and processed.
BGP routers and route reflectors (RRs) propagate only their best path over their sessions. The advertisement of a
prefix replaces the previous announcement of that prefix (this behavior is known as an implicit withdraw). The implicit
withdraw can achieve better scaling, but at the cost of path diversity.
Path hiding can prevent efficient use of BGP multipath, prevent hitless planned maintenance, and can lead to MED
oscillations and suboptimal hot-potato routing. Upon nexthop failures, path hiding also inhibits fast and local recovery
because the network has to wait for BGP control plane convergence to restore traffic. The BGP Additional Paths
feature provides a generic way of offering path diversity; the Best External or Best Internal features offer path
diversity only in limited scenarios.
The BGP Additional Paths feature provides a way for multiple paths for the same prefix to be advertised without the
new paths implicitly replacing the previous paths. Thus, path diversity is achieved instead of path hiding.
References: http://www.cisco.com/en/US/docs/ios-xml/ios/iproute_bgp/configuration/15-1sg/irg-nexthop-
track.html
http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/iproute_bgp/configuration/xe-3s/irg-xe-3s-
book/bgp_additional_paths.html

NEW QUESTION: 3
Which two commands are required to enable multicast on a router, knowing that the receivers only support IGMPv2? (Choose two.)
A. ip pim rp-address
B. ip pim sparse-mode
C. ip pim ssm
D. ip pim passive
Answer: A,B
Explanation:
Sparse mode logic (pull mode) is the opposite of Dense mode logic (push mode), in Dense mode it is supposed that in every network there is someone who is requesting the multicast traffic so PIM-DM routers begin by flooding the multicast traffic out of all their interfaces except those from
where a prune message is received to eliminate the "leaf" from the multicasting tree (SPT), the Source-Based Tree (S, G); as opposed to Sparse mode that send the traffic only if someone explicitly requested it.
Not like Dense mode, which build a separated source-based tree (S, G) between the source and the requester of the traffic, Sparse mode mechanism is based on a fixed point in the network named Rendez-Vous point.
All sources will have to register with the RP to which they send their traffic and thereby build a source-based tree (S, G) between them and the RP (not with the final multicast receiver like in PIM-DM) and all PIM-SM routers, "whatever" multicast traffic they are requesting, have to register with the RP and build a shared-tree (*. G)
Reference http://tools.ietf.org/html/rfc2236 http://www.cisco.com/en/US/products/hw/switches/ps708/products_tech_note09186a00800b0871. shtml http://www.cisco.com/en/US/tech/tk828/technologies_tech_note09186a0080094821.shtml#sparse mode

NEW QUESTION: 4

public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}

A. try {Files.copy(Paths.get(source), Paths.get(dest));
Files.delete(Paths.get(source));
B. try {FileChannel in = new FileInputStream(source).getChannel();
FileChannel out = new FileOutputStream(dest).getChannel ();
in.transferTo (0, in.size(), out);
C. try {Files.copy(Paths.get(source), Paths.get(dest));
Files.delete(Paths.get(source));
D. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName ("UTF-
8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8"));
String record = "";
while ((record = br.readLine()) != null){
bw.write (record);
bw.newLine();
}
Files.delete(Paths.get(source));
E. try {Files.move (Paths.get(source), Paths.get(dest));
Answer: A,E


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