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Exam Code: NSE5_FSM-6.3
Exam Name: Fortinet NSE 5 - FortiSIEM 6.3
Vendor: Fortinet

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NEW QUESTION: 1
A network administrator creates a static route that points directly to a multi-access interface, instead of the next-hop IP address. The administrator notices that Cisco Express Forwarding ARP requests are being sent to all destinations. Which issue might this configuration create?
A. low bandwidth usage
B. high memory usage
C. high bandwidth usage
D. IP route interference
E. Cisco Express Forwarding routing loop
Answer: E
Explanation:
Explanation/Reference:
References:

NEW QUESTION: 2
Lab Simulation Question - CLI
Central Florida Widgets recently installed a new router in their office. Complete the network installation by performing the initial router configurations and configuring R1PV2 routing using the router command line interface (CLI) on the RC.
Configure the router per the following requirements:
- Name of the router is R2
- Enable.secret password is cisco
- The password to access user EXEC mode using the console is cisco2
- The password to allow telnet access to the router is cisco3
IPV4 addresses mast be configured as follows:
- Ethernet network 209.165.201.0/27 - router has fourth assignable host address in subnet
- Serial network is 192.0.2.176/28 - router has last assignable host
address in the subnet.
- Interfaces should be enabled.
- Router protocol is RIPV2
Attention:
In practical examinations, please note the following, the actual information will prevail.
1. Name or the router is xxx
2. EnablE. secret password is xxx
3. Password In access user EXEC mode using the console is xxx
4. The password to allow telnet access to the router is xxx
5. IP information

Answer:
Explanation:
Step 1:
Click on the console host, you will get a pop-up screen CLI of Router.
Router>
Configure the new router as per the requirements provided in Lab question Requirement 1:
Name of the router is R2
Step 2:
To change the hostname of the router to R2 follow the below steps:
Router>
Router>enable
Router#configure terminal
Router(config)#hostname R2
R2(config)#
Requirement 2:
Enable-secret password is cisco1
Step 3:
To set the enable secret password to cisco1 use the following command
R2(config)#enable secret cisco1
Requirement 3:
The password to access user EXEC mode using the console is cisco2
Step 4:
We need to configure the line console 0 with the password cisco2
Also remember to type login command after setting up the password on line con 0 which allows router to accept logins via console.
R2(config)#line con 0
R2(config-line)#password cisco2
R2(config-line)#login
R2(config-line)#exit
R2(config)#
Requirement 4:
The password to allow telnet access to the router is cisco3
Step 5:
To allow telnet access we need to configure the vty lines 0 4 with the password cisco3 Also remember to type login command after setting up the password on line vty 0 4 which allows router to accept logins via telnet.
R2(config)#line vty 0 4
R2(config-line)#password cisco3
R2(config-line)#login
R2(config-line)#exit
R2(config)#
Requirement 5:
(5.1) Ethernet network 209.165.201.0 /27 - Router has the fourth assignable host address in subnet.
(5.2) Serial Network is 192.0.2.176 /28 - Router has the last assignable host address in subnet.
Step 6:
Ethernet network 209.165.201.0 /27 - Router has the fourth assignable host address in subnet.
Ethernet Interface on router R2 is Fast Ethernet 0/0 as per the exhibit First we need to identify the subnet mask Network: 209.165.201.0 /27 Subnet mask: /27: 27 bits = 8 + 8 + 8 + 3
=8(bits).8(bits).8(bits) .11100000 (3bits)
=255.255.255.11100000
=11100000 = 128+64+32+0+0+0+0+0
= 224
Subnet mask: 255.255.255.224
Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks :::::: Valid Host address range :::::: Broadcast address
209.165.201.0 :::::: 209.165.201.1 - 209.165.201.30 ::::: 209.165.201.31
209.165.201.32 :::::: 209.165.201.33 - 209.165.201.62 ::::: 209.165.201.63
209.165.201.64 :::::: 209.165.201.65 - 209.165.201.94 :::::: 209.165.201.95
209.165.201.96 :::::: 209.165.201.97 - 209.165.201.126 :::::: 209.165.201.127
209.165.201.128 :::::: 209.165.201.129 - 209.165.201.158 :::::: 209.165.201.159
209.165.201.160 :::::: 209.165.201.161 - 209.165.201.190 :::::: 209.165.201.191
209.165.201.192 :::::: 209.165.201.193 - 209.165.201.222 :::::: 209.165.201.223
209.165.201.224 :::::: 209.165.201.225 - 209.165.201.254 :::::: 209.165.201.255 Use above table information for network 209.165.201.0 /27 to identify First assignable host address: 209.165.201.1 Last assignable host address: 209.165.201.30 Fourth assignable host address: 209.165.201.4 This IP address (209.165.201.4) which we need to configure on Fast Ethernet 0/0 of the router using the subnet mask 255.255.255.224 R2(config)#interface fa 0/0 R2(config-if)#ip address 209.165.201.4 255.255.255.224 Requirement 6:
To enable interfaces
Use no shutdown command to enable interfaces
R2(config-if)#no shutdown
R2(config-if)#exit
Step 7:
Serial Network is 192.0.2.176 /28 - Router has the last assignable host address in subnet.
Serial Interface on R2 is Serial 0/0/0 as per the exhibit
First we need to identify the subnet mask
Network: 192.0.2.176 /28
Subnet mask: /28: 28bits = 8bits+8bits+8bits+4bits
=8(bits).8(bits).8(bits) .11110000 (4bits)
=255.255.255.11100000
=11100000 = 128+64+32+16+0+0+0+0
= 240
Subnet mask: 255.255.255.240
Different subnet networks and there valid first and last assignable host address range for above subnet mask are Subnet Networks ::::: Valid Host address ::::::::::: Broadcast address
192.0.2.0 :::::: 192.0.2.1 - 192.0.2.14 ::::::: 192.0.2.15
192.0.2.16 ::::::: 192.0.2.17 - 192.0.2.30 ::::::: 192.0.2.31
192.0.2.32 :::::::: 192.0.2.33 - 192.0.2.46 :::::: 192.0.2.47
192.0.2.48 :::::: 192.0.2.49 - 192.0.2.62 ::::::: 192.0.2.64
192.0.2.64 ::::::: 192.0.2.65 - 192.0.2.78 ::::::: 192.0.2.79
192.0.2.80 :::::::: 192.0.2.81 - 192.0.2.94 :::::: 192.0.2.95
192.0.2.96 :::::: 192.0.2.97 - 192.0.2.110 ::::::: 192.0.2.111
192.0.2.112 ::::::: 192.0.2.113 - 192.0.2.126 ::::::: 192.0.2.127
192.0.2.128 :::::::: 192.0.2.129 - 192.0.2.142 :::::: 192.0.2.143
192.0.2.144 :::::: 192.0.2.145 - 192.0.2.158 ::::::: 192.0.2.159
192.0.2.160 ::::::: 192.0.2.161 - 192.0.2.174 ::::::: 192.0.2.175
192.0.2.176 :::::::: 192.0.2.177 - 192.0.2.190 :::::: 192.0.2.191
and so on ....
Use above table information for network 192.0.2.176 /28 to identify
First assignable host address: 192.0.2.177
Last assignable host address: 192.0.2.190
We need to configure Last assignable host address (192.0.2.190) on serial 0/0/0 using the subnet mask 255.255.255.240 R2(config)#interface serial 0/0/0 R2(config-if)#ip address 192.0.2.190 255.255.255.240 Requirement 6:
To enable interfaces
Use no shutdown command to enable interfaces
R2(config-if)#no shutdown
R2(config-if)#exit
Requirement 7:
Router protocol is RIPv2
Step 8:
Need to enable RIPv2 on router and advertise its directly connected networks R2(config)#router rip To enable RIP v2 routing protocol on router use the command version 2 R2(config-router)#version 2 Optional: no auto-summary (Since LAB networks do not have discontinuous networks) RIP v2 is classless, and advertises routes including subnet masks, but it summarizes routes by default.
So the first things we need to do when configuring RIP v2 is turn off auto-summarization with the router command no auto-summary if you must perform routing between disconnected subnets.
R2 (config-router) # no auto-summary
Advertise the serial 0/0/0 and fast Ethernet 0/0 networks into RIP v2 using network command R2(config-router)#network 192.0.2.176 R2(config-router)#network 209.165.201.0 R2(config-router)#end Step 9:
Important please do not forget to save your running-config to startup-config R2# copy running-config startup-config

NEW QUESTION: 3
Let E(X ) = 1, E(Y ) = 3, Corr(X, Y ) = -0.2, E(X2 ) = 10 and E(Y2 ) = 13. Find the covariance between X and Y
A. None of the above
B. -2.8
C. -1.2
D. 1.3
Answer: C

NEW QUESTION: 4
Which of the following is the best method for requesting data from an SQL database? (Choose One)
A. Service package
B. SQL connector
C. External database table class mapping
D. SQL listener
Answer: C


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