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NEW QUESTION: 1
스토리지에 RAIDed EBS 볼륨 집합을 사용하는 EC2에서 관계형 데이터베이스를 백업하는 절차로 인해 데이터베이스를 쓸 수 없으며 일관된 백업이 이루어지는 시간을 최소화 할 수 있습니까?
A. 1. EC2 인스턴스를 중지하십시오. 2. EBS 볼륨 스냅 샷
B. 1. 디스크 1/0을 일시 중단합니다. 2. 볼륨의 EBS 스냅 샷을 시작합니다. 3. 스냅 샷이 완료 될 때까지 기다립니다. 4. 디스크 1/0을 다시 시작합니다.
C. 1. 디스크 1/0을 일시 중단합니다. 2. EC2 인스턴스의 이미지를 만듭니다. 3. 디스크 1/0을 다시 시작합니다.
D. 1. EBS 볼륨 분리, 2. 볼륨의 EBS 스냅 샷 시작, 3. EBS 볼륨 다시 연결
E. 1. 디스크 1/0을 일시 중단합니다. 2. 볼륨의 EBS 스냅 샷을 시작합니다. 3. 디스크 1/0을 다시 시작합니다.
Answer: D
Explanation:
설명:
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NEW QUESTION: 2
A major benefit of computer integrated manufacturing CIM) is:
A. Increased working capital.
B. Increased amount of scrap available for resale.
C. Delivery of customized products with long lead times.
D. Increased flexibility.
Answer: D
Explanation:
CIM entails a holistic approach to manufacturing in which design is translated into product by centralized processing and robotics. CIM can help an organization reduce costs of spoilage, increase flexibility, and increase productivity. Flexibility is the key benefit. A traditional manufacturing system might become disrupted from an emergency change, but CII1 will reschedule everything in the plant when a priority requirement is inserted into the system.
NEW QUESTION: 3
A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the attacker by studying the log. Please note that you are required to infer only what is explicit in the excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting, basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.) 03/15-20:21:24.107053 211.185.125.124:3500 ->
172.16.1.108:111 TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF ***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32 TCP Options (3) => NOP NOP TS: 23678634 2878772 =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= +=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111 UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84 Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................ 00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................ 00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= +=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773 UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104 Len: 1084 47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8
A. The attacker has conducted a network sweep on port 111
B. The attacker has installed a backdoor
C. The attacker has used a Trojan on port 32773
D. The attacker has scanned and exploited the system using Buffer Overflow
Answer: A
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