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NEW QUESTION: 1
マルチキャストアドレスに関する2つの説明のうち正しいものはどれですか？ （2つ選択）
A. 01-00-53-ab-11-c1はマルチキャストMACアドレスです
B. 02-00-5e-7f-11-c1はマルチキャストMACアドレスです
C. 1対1の通信が可能
D. 1対多のコミュニケーションが可能
E. 01-00-5e-7b-11-c1はマルチキャストMACアドレスです
Answer: A,E

NEW QUESTION: 2
Switches maintain a CAM Table that maps individual MAC addresses on the network to physical ports on the switch.

In MAC flooding attack, a switch is fed with many Ethernet frames, each containing different source MAC addresses, by the attacker. Switches have a limited memory for mapping various MAC addresses to physical ports. What happens when the CAM table becomes full?
A. The switch replaces outgoing frame switch factory default MAC address of FF:FF:FF:FF:FF:FF
B. Switch then acts as hub by broadcasting packets to all machines on the network
C. Every packet is dropped and the switch sends out SNMP alerts to the IDS port
D. The CAM overflow table will cause the switch to crash causing Denial of Service
Answer: B

NEW QUESTION: 3
Which two Cisco Products can demonstrate the "one policy" approach in the Cisco unified access solution? (choose two)
A. Cisco AnyConnect
B. Catalyst 6500 series switch
C. Cisco ISE
D. Cisco mobility services engine
E. Cisco WLC
Answer: A,C

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) csWHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountryFROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D

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