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NEW QUESTION: 1
A wireless phone user is having roaming difficulties and is experiencing gaps in the conversation while roaming.
WLC WLAN is configured as IEEE 802.1X and WPA2 and Aironet information element. What should be configured to fix the problem?
A. IEEE 802.1X with Cisco Centralized Key Management
B. IEEE 802.1X EAP-FAST
C. DHCP required and DHCP proxy on WLC
D. WPA1 and PSK
Answer: A
Explanation:
Explanation
https://www.cisco.com/c/en/us/td/docs/wireless/controller/8-1/Enterprise-Mobility-8-1-Design-Guide/ Enterprise_Mobility_8-1_Deployment_Guide.pdf
NEW QUESTION: 2
You are modifying a blog site to improve search engine readability.
You need to group relevant page content together to maximize search engine readability.
Which tag should you use?
A. <span>
B. <section>
C. <cable>
D. <nav>
Answer: B
Explanation:
Explanation
The <section> tag defines sections in a document. Such as chapters, headers, footers, or any other sections of the document.
NEW QUESTION: 3
According to IDC, what is the attitude of most Global 500 companies toward digital transformation?
A. They have completed their digital transformation products and are turning their attention to the next trend.
B. They are waiting to see if their competitors are successful in implementing it.
C. They are committed to it and have formed dedicatee digital transformation teams.
D. They are skeptical that it will provide a return on investment.
Answer: C
NEW QUESTION: 4
Refer to the exhibit.
Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.16 255.255.255.240
B. 192.168.25.16 255.255.255.252
C. 192.168.25.0 255.255.255.240
D. 192.168.25.28 255.255.255.252
E. 192.168.25.28 255.255.255.240
F. 192.168.25.0 255.255.255.252
Answer: A
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+
192.168.25.16
+
192.168.25.20
+
192.168.25.24
+
192.168.25.28 -> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
255.255.255.240
So the best answer should be 192.168.25.16 255.255.255.240
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