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Exam Code: JN0-664
Exam Name: Service Provider, Professional (JNCIP-SP)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1

A. Option C
B. Option A
C. Option B
D. Option D
Answer: B
Explanation:
- Scenario: Database2 will contain a stored procedure named usp_UpdateInventory.
Usp_UpdateInventory will manipulate a table that contains a self-join that has an unlimited number of hierarchies.
- A table variable can be very useful to store temporary data and return the data in the table format.
- Example: The following example uses a self-join to find the products that are supplied by more than one vendor. Because this query involves a join of the ProductVendor table with itself, the ProductVendor table appears in two roles. To distinguish these roles, you must give the ProductVendor table two different aliases (pv1 and pv2) in the FROM clause.
These aliases are used to qualify the column names in the rest of the query. This is an example of the self-join Transact-SQL statement:


NEW QUESTION: 2
CORRECT TEXT
You have been tasked with configuring multilayer SwitchC, which has a partial configuration and has been attached to RouterC as shown in the topology diagram.
You need to configure SwitchC so that Hosts H1 arid H2 can successful ping the server S1. Also SwitchC needs to be able to ping server SI.
Due to administrative restrictions and requirements you should not add/delete vlans or create trunk links Company policies forbid the use of static or default routing All routes must be learned via EIGRP 65010 routing protocol.
You do not have access to RouteC, RouterC is correctly configured. No trunking has been configured on RouterC.
Routed interfaces should use the lowest host on a subnet when possible. The following subnets are available to implement this solution:
172.16.1.0/24
192.168.3.32/27
192.168.3.64/27
Hosts H1 and H2 are configured with the correct IP address and default gateway.
SwitchC uses Cisco as the enable password.
Routing must only be enabled for the specific subnets shown in the diagram.
Note: Due to administrative restrictions and requirements you should not add or delete VLANs, changes VLAN port assignments or create trunks. Company policies forbid the use of static or default routing. All routes must be learning via the EIGRP routing protocol.

HOST 1

HOST 2

Answer:
Explanation:
Here are Step by Step Configuration:
Explanation:
In real life, there are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC.+ Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer 3 switch (which supports ip routing function as a router). No trunking requires. The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing. We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways. C:\>ipconfig We will get the default gateways as follows: Host1:+ Default gateway: 192.168.3.33 Host2:+ Default gateway: 192.168.3.65 Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 65010) Note: VLAN2 and VLAN3 were created and gi0/15, gi0/16 interfaces were configured as access ports so we don't need to configure them in this sim. SwitchC# configure terminalSwitchC(config)# int gi0/1SwitchC(config-if)#no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface.SwitchC(config-if)# ip address 172.16.1.2 255.255.255.0 ->RouterC has used IP
172.16.1.1 so this is the lowest usable IP address.SwitchC(config-if)# no shutdown SwitchC(config-if)# exitSwitchC(config)# int vlan 2SwitchC(config-if)# ip address 192.168.3.33 255.255.255.224SwitchC(config-if)# no shutdownSwitchC(config-if)# int vlan 3SwitchC(configif)# ip address 192.168.3.65 255.255.255.224SwitchC(config-if)# no shutdownSwitchC(configif)#exitSwitchC(config)# ip routing (Notice: MLS will not work without this command)SwitchC(config)# router eigrp 65010SwitchC(config-router)# network 172.16.1.0 0.0.0.255SwitchC(config-router)# network 192.168.3.32 0.0.0.31SwitchC(config-router)# network 192.168.3.64 0.0.0.31
NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam, also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 192.168.0.0/16 is not used anywhere else in this topology. After configure everything you should check the routing table of SwitchC (with the "show ip route" command") to see if there are any EIGRP entries there. Also try pinging from Host1 & Host2 to the Server S1. If the pings are successful then your configuration is correct. Also make sure you use the correct EIGRP AS number (in the configuration above it is 65010 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC. In fact, we are pretty sure instead of using two commands "network 192.168.3.32 0.0.0.31 and "network 192.168.3.64 0.0.0.31 we can use one simple command "network 192.168.0.0 because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without "no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 192.168.0.0 is shown.

NEW QUESTION: 3
A situation in which an owner of more than 50% of voting shares can elect the entire board of directors is known as
A. Straight voting
B. Cumulative voting
C. Discretionary voting
D. Distributed voting
Answer: A

NEW QUESTION: 4
Sie erwerben ein neues Microsoft 365-Abonnement.
Sie erstellen 100 Benutzer, denen Microsoft 365 E3-Lizenzen zugewiesen wurden.
Im Security & Compliance Admin Center aktivieren Sie die Überwachung.
Sechs Monate später sendet Ihnen ein Manager eine E-Mail mit den folgenden Fragen:
Frage 1: Wer hat vor 14 Tagen ein Team namens Team1 erstellt?
Frage 2: Wer hat sich vor 30 Tagen im Postfach von Benutzer 1 angemeldet?
Frage 3: Wer hat vor 60 Tagen die Websitesammlungsadministratoren einer Website geändert?
Wählen Sie für jede der folgenden Anweisungen Ja aus, wenn die Anweisung wahr ist. Andernfalls wählen Sie Nein.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.

Answer:
Explanation:

Explanation

References:
https://docs.microsoft.com/en-us/office365/securitycompliance/search-the-audit-log-in-security-and-compliance?
https://docs.microsoft.com/en-us/office365/securitycompliance/enable-mailbox-auditing


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