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Exam Code: JN0-214
Exam Name: Cloud, Associate (JNCIA-Cloud)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1

A. Option C
B. Option E
C. Option B
D. Option D
E. Option A
Answer: D
Explanation:
Explanation
http://surachartopun.com/2010/06/ddl-on-tables-enabled-for-flashback.html

NEW QUESTION: 2
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario verwenden. Zur Vereinfachung wird das Szenario in jeder Frage wiederholt. Jede Frage stellt ein anderes Ziel und eine andere Antwortauswahl dar, aber der Text des Szenarios ist in jeder Frage dieser Reihe genau gleich.
Beginn des wiederholten Szenarios
Ihr Netzwerk enthält eine Active Directory-Domäne mit dem Namen contoso.com. Die Funktionsebene der Domäne ist Windows Server 2012.
Das Netzwerk verwendet einen Adressraum von 192.168.0.0/16 und enthält mehrere Subnetze.
Das Netzwerk ist nicht mit dem Internet verbunden.
Die Domäne enthält drei Server, die wie in der folgenden Tabelle gezeigt konfiguriert sind.

Clientcomputer beziehen TCP / IP-Einstellungen von Server3.
Sie fügen Server2 einen zweiten Netzwerkadapter hinzu. Sie verbinden den neuen Netzwerkadapter mit dem Internet. Sie installieren den Routing-Rollendienst auf Server2.
Server1 verfügt über vier DNS-Zonen, die wie in der folgenden Tabelle gezeigt konfiguriert sind.

Ende des wiederholten Szenarios
Sie müssen sicherstellen, dass die Abfrageergebnisse beim Abfragen von Datensätzen auf tailspintoys.com auf dem Subnetz des Computers basieren, der die Abfrage generiert.
Was tun?
A. Erstellen Sie Zonendelegierungsdatensätze.
B. Ändern Sie die Prioritätseinstellungen der einzelnen Ressourceneinträge.
C. DNS-Round-Robin aktivieren.
D. DNS-Richtlinien konfigurieren.
Answer: D

NEW QUESTION: 3
The LTM device is configured to provide load balancing to a set of web servers that implement access control lists (ACL) based on the source IP address of the client. The ACL is at the network level and the web server is configured to send a TCP reset back to the client if it is NOT permitted to connect.
The virtual server is configured with the default OneConnect profile.
The ACL is defined on the web server as:
Permit: 192.168.136.0/24
Deny: 192.168.116.0/24
The packet capture is taken of two individual client flows to a virtual server with IP address
192.168.136.100.
Client A - Src IP 192.168.136.1 - Virtual Server 192.168.136.100:
Clientside:
09:35:11.073623 IP 192.168.136.1.55684 > 192.168.136.100.80: S 869998901:869998901(0) win 8192
<mss 1460,nop,wscale 2,nop,nop,sackOK>
09:35:11.073931 IP 192.168.136.100.80 > 192.168.136.1.55684: S 2273668949:2273668949(0) ack
869998902 win 4380 <mss 1460,nop,wscale 0,sackOK,eol>
09:35:11.074928 IP 192.168.136.1.55684 > 192.168.136.100.80: . ack 1 win 16425
09:35:11.080936 IP 192.168.136.1.55684 > 192.168.136.100.80: P 1:299(298) ack 1 win 16425
09:35:11.081029 IP 192.168.136.100.80 > 192.168.136.1.55684: . ack 299 win 4678 Serverside:
09:35:11.081022 IP 192.168.136.1.55684 > 192.168.116.128.80: S 685865802:685865802(0) win 4380
<mss 1460,nop,wscale 0,sackOK,eol>
09:35:11.081928 IP 192.168.116.128.80 > 192.168.136.1.55684: S 4193259095:4193259095(0) ack
685865803 win 5840 <mss 1460,nop,nop,sackOK,nop,wscale 6>
09:35:11.081943 IP 192.168.136.1.55684 > 192.168.116.128.80: . ack 1 win 4380
09:35:11.081955 IP 192.168.136.1.55684 > 192.168.116.128.80: P 1:299(298) ack 1 win 4380
09:35:11.083765 IP 192.168.116.128.80 > 192.168.136.1.55684: . ack 299 win 108 Client B - Src IP 192.168.116.1 - Virtual Server 192.168.136.100:
Clientside:
09:36:11.244040 IP 192.168.116.1.55769 > 192.168.136.100.80: S 3320618938:3320618938(0) win 8192
<mss 1460,nop,wscale 2,nop,nop,sackOK>
09:36:11.244152 IP 192.168.136.100.80 > 192.168.116.1.55769: S 3878120666:3878120666(0) ack
3320618939 win 4380 <mss 1460,nop,wscale 0,sackOK,eol>
09:36:11.244839 IP 192.168.116.1.55769 > 192.168.136.100.80: . ack 1 win 16425
09:36:11.245830 IP 192.168.116.1.55769 > 192.168.136.100.80: P 1:299(298) ack 1 win 16425
09:36:11.245922 IP 192.168.136.100.80 > 192.168.116.1.55769: . ack 299 win 4678 Serverside:
09:36:11.245940 IP 192.168.136.1.55684 > 192.168.116.128.80: P 599:897(298) ack 4525 win 8904
09:36:11.247847 IP 192.168.116.128.80 > 192.168.136.1.55684: P 4525:5001(476) ack 897 win 142 Why was the second client flow permitted by the web server?
A. A global SNAT is defined.
B. SNAT automap was enabled on the virtual server.
C. The idle TCP session from the first client was re-used.
D. A source address persistence profile is assigned to the virtual server.
Answer: C


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