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Exam Code: JN0-1103
Exam Name: Design, Associate (JNCIA-Design)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
十分に開発されたマネーロンダリング防止コンプライアンスプログラムが、制度的な目標を達成する可能性はありません。
A. アカウント所有者の確認。
B. 適切な従業員のトレーニング。
C. 管轄当局による承認。
D. すべてのスタッフをスクリーニングします。
Answer: C

NEW QUESTION: 2
Which of the following devices can be utilized to monitor and block websites accessible by a company?
A. DNS server
B. WINS server
C. Reverse proxy
D. Content filter
Answer: D

NEW QUESTION: 3
What statements are true about 802.11-2012 Protected Management Frames? (Choose 2)
A. Authentication, association, and acknowledgment frames are protected if management frame protection is enabled, but deauthentication and disassociation frames are not.
B. Management frame protection protects disassociation and deauthentication frames.
C. When frame protection is in use, the PHY preamble and header as well as the MAC header are encrypted with 256- or 512-bit AES.
D. 802.11w frame protection protects against some Layer 2 denial-of-service (DoS) attacks, but it cannot prevent all types of Layer 2 DoS attacks.
Answer: B,D

NEW QUESTION: 4
Which of the following is an advantage of asymmetric crypto system over symmetric key crypto system?
A. Key Management is built in
B. Number of keys grows very quickly
C. Adequate for Bulk encryption
D. Performance and Speed
Answer: A
Explanation:
Explanation/Reference:
Key management is better in asymmetric key encryption as compare to symmetric key encryption. In fact, there is no key management built within Symmetric Crypto systems. You must use the sneaker net or a trusted courier to exchange the key securely with the person you wish to communicate with.
Key management is the major issue and challenge in symmetric key encryption.
In symmetric key encryption, a symmetric key is shared between two users who wish to communicate together. As the number of users grows, the number of keys required also increases very rapidly.
For example, if a user wants to communicate with 5 different users then total number of different keys required by the user are 10. The formula for calculating total number of key required is n(n-1)/2Or total number of users times total of users minus one divided by 2.
Where n is number of users communicating with each others securely.
In an asymmetric key encryption, every user will have only two keys, also referred to as a Key Pair.
Private Key - Only known to the user who initially generated the key pair Public key - Known to everyone, can be distributed at large The following were incorrect answers:
Performance - Symmetric key encryption performance is better than asymmetric key encryption Bulk encryption - As symmetric key encryption gives better performance, symmetric key should be used for bulk data encryption Number of keys grows very quickly - The number of keys under asymmetric grows very nicely.1000 users would need a total of only 2000 keys, or a private and a public key for each user. Under symmetric encryption, one thousand users would need 495,000 keys to communicate securely with each others.
The following reference(s) were/was used to create this question:
CISA review manual 2014 Page number 348


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