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NEW QUESTION: 1
You are working in a multi-user central repository based environment. You select "Rename owner" on an object which is not checked out. The object has one or more dependent objects in the local repository. What is the outcome?
A. Data Integrator renames the individual object owner.
B. Data integrator displays a second window listing the dependent objects. when you click "continue" the object owner is renamed and all of the dependent objects are modified.
C. Data Integrator renames the owner of all 0bjects within the selected data store.
D. Data Integrator displays the "This object is checked out from central repository "X". Please select Tools Central Repository. to activate that repository before renaming Message.
Answer: B
NEW QUESTION: 2
A VPC is connected to a company data center by a VPN. An Amazon EC2 instance with the IP address
172.31.16.139 is within a private subnet of the VPC. A SysOps Administrator issued a ping command to the EC2 instance from an on-premises computer with the IP address 203.0.113.12 and did not receive an acknowledgment. VPC Flow Logs were enabled and showed the following:
What action will resolve the issue?
A. Modify the VPC network ACL rules to allow inbound traffic from the on-premises computer
B. Modify the VPC network ACL rules to allow outbound traffic to the on-premises computer
C. Modify the EC2 security group rules to allow outbound traffic to the on-premises computer
D. Modify the EC2 security group rules to allow inbound traffic from the on-premises computer
Answer: C
NEW QUESTION: 3
Why would a technician use a password cracker?
A. To look for weak passwords on the network
B. To change a user's passwords when they leave the company
C. To enforce password complexity requirements
D. To change users passwords if they have forgotten them
Answer: A
Explanation:
A password cracker will be able to expose weak passwords on a network.
NEW QUESTION: 4
* MainOffice 172.16.1.0 Subnet: 255.255.255.0 Gateway 172.16.1.254
* Site1 192.168.12.0 Subnet: 255.255.255.0
* Site 2 192.168.13.0 Subnet: 255.255.255.0
* Site 3 192.168.14.0 Subnet: 255.255.255.0
* Site 4 192.168.15.0 Subnet: 255.255.255.0
A. route add -p 192.168.12.0 netmask 255.255.240.0 172.16.1.254
B. route add -p 192.168.0.0 netmask 255.255.248.0 172.16.1.254
C. route add -p 192.168.12.0 netmask 255.255.252.0 172.16.1.254
D. route add -p 192.168.8.0 netmask 255.255.252.0 172.16.1.254
Answer: C
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