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Exam Code: 1z1-829
Exam Name: Java SE 17 Developer
Vendor: Oracle

60 Questions & Answers
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NEW QUESTION: 1

A. 192.168.1.32/27
B. 192.168.1.40/29
C. 192.168.1.8/29
D. 192.168.1.16/28
E. 192.168.1.48/29
Answer: B
Explanation:
Explanation
248 mask uses 5 bits (1111 1000) 42 IP in binary is (0010 1010) The base subnet therefore is the lowest binary value that can be written without changing the output of an AND operation of the subnet mask and IP ... 1111
1000 AND 0010 1010 equals 0010 1000 - which is .40 /24 is standard class C mask. adding the 5 bits from the .248 mask gives /29

NEW QUESTION: 2

A. Option A
B. Option C
C. Option B
D. Option D
Answer: C

NEW QUESTION: 3
You are asked to configure an SRX Series device to bypass all security features for IP traffic from the engineering department.
Which firewall filter will accomplish this task?
A)

B)

C)

D)

A. Option D
B. Option B
C. Option A
D. Option C
Answer: A


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