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Exam Code: JN0-664
Exam Name: Service Provider, Professional (JNCIP-SP)
Vendor: Juniper

60 Questions & Answers
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NEW QUESTION: 1
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.1.0.0.0.254
B. Permit 10.0.0.0.0.0.0.1
C. Permit 10.0.0.0.255.255.255.254
D. Permit 10.0.0.1.0.0.0.0
Answer: A
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 2
What is the purpose of the SAP S/4HANA simplification list?
A. To indicate functions of SAP S/4HANAthat are not yet available
B. To provide custom code analysis that can be moved to S/4HANA
C. To perform real time data migration within SAP S/4HANA
D. To provide a list of new SAP Fiori applications
Answer: B

NEW QUESTION: 3
A company has an existing point to point application written in C that distributes delivery status to queue Q1. They want to change the distribution to publish/subscribe so that other applications can subscribe to the delivery status information. Which of the following ways of changing to WebSphere MQ publish/subscribe will work with the least recoding?
A. Change the sending application program to use the WebSphere MQ publish/subscribe APIinstead of point to point
B. Change the sending application program to use WebSphere MQ publish/subscribe commandsin RFH2 headers instead of the point to point API
C. Run WebSphere MQ in PSMODE=COMPAT
D. Set up a queue alias for Q1 that is an alias for a subscription topic
Answer: D

NEW QUESTION: 4
Während eines Änderungskontroll-Audits eines Produktionssystems stellt ein IS-Auditor fest, dass der Änderungsmanagementprozess nicht formal dokumentiert ist und einige Migrationsverfahren fehlgeschlagen sind. Was soll der IS-Prüfer als nächstes tun?
A. Dokumentieren Sie den Befund und legen Sie ihn dem Management vor.
B. Es wird empfohlen, die Programmmigration zu stoppen, bis der Änderungsprozess dokumentiert ist.
C. Empfehlen Sie die Neugestaltung des Änderungsverwaltungsprozesses.
D. Gewinnen Sie durch Ursachenanalysen mehr Gewissheit über die Ergebnisse.
Answer: D
Explanation:
Erläuterung:
Ein Change Management-Prozess ist für IT-Produktionssysteme von entscheidender Bedeutung. Bevor der IS-Prüfer dem Unternehmen empfiehlt, andere Maßnahmen zu ergreifen (z. B. Migrationen zu stoppen, den Änderungsmanagementprozess neu zu gestalten), sollte er sich vergewissern, dass die gemeldeten Vorfälle mit Mängeln im Änderungsmanagementprozess zusammenhängen und nicht durch andere Prozesse als Änderungen verursacht werden Verwaltung.


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