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Exam Code: D-NWR-DY-23
Exam Name: Dell NetWorker Deploy 23
Vendor: EMC

60 Questions & Answers
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NEW QUESTION: 1
Use DOM programming to create XML according to the schema defined by TravelXML (portions modified for this question). Create XML according to the method shown by "DOM Processing". Select which of the following correctly describes the results of performing a validation check on the created XML against the schema ("XML Schema" referenced when the Exhibit Button is pushed).
[DOM Processing]
Create XML using the following method.
Document doc = createXML( impl );
The variable impl here references the DOMImplementation instance.
The DOM parser is namespace aware.
Assume no execution errors.
A. The created XML is valid
B. The created XML includes all of the required elements defined by the schema (all elements defined once they have appeared, namespace refleted); however, is not valid
C. The created XML does not include the required elements defined by the schema (all elements defined once they have appeared, namespace reflected); therefore, is not valid
D. The root element (document element) of the created XML is an empty element, and the created XML is not valid against the schema
Answer: B

NEW QUESTION: 2
Match each type of NAT with the correct description:
Conserves IP addresses and hides the internal topology of your network. (Choose one)
A. NAT Loopback
B. Dynamic NAT
C. 1-to1 NAT
Answer: A
Explanation:
Dynamic NAT is also known as IP masquerading.With dynamic NAT many computers can connect to the Internet from one public IP address. Dynamic NAT gives more security for internal hosts that use the Internet, because it hides the IP addresses of hosts on your network.
Reference:http://www.watchguard.com/help/docs/wsm/xtm_11/en-US/index.html#en-US/nat/nat_dynamic_use_c.html%3FTocPath%3DNetwork%2520Address%2520Translation%252 0(NAT)%7CAbout%2520Dynamic%2520NAT%7C_____0

NEW QUESTION: 3
DRAG DROP
You have a System Center 2012 R2 Configuration Manager Service Pack 1 (SP1) deployment.
You need to implement anti-virus protection for all Configuration Manager clients. The solution must ensure that servers have different anti-virus settings than client computers.
In which order should you perform the required actions? To answer drag the appropriate actions to the correct locations. Each action may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.

Answer:
Explanation:

Explanation:

Step 1: EndPoint Protection
When System Center 2012 Endpoint Protection isused with Microsoft System Center 2012
Configuration Manager, it provides a comprehensive enterprise management solution that lets you do the following:
* Centrally deploy and configure the EndpointProtection client.
* Configure default and custom antimalware policies that apply to groups of computers.
Etc
Step 2:
Client settings for devices include Endpoint Protection.
All client settings in System Center 2012 Configuration Manager are managed in the
Configuration Manager console from the Client Settingsnode in the Administration workspace. A set of default settings is supplied with Configuration Manager. When you modify the default client settings, these settings are applied to all clients in thehierarchy.
You can also configure custom client settings,which override the default client settings when you assign these to collections.

NEW QUESTION: 4
An 802.11n implementation is being discussed. Users are satisfied with the potential 300-450 Mbps throughput of new 802.11n APs. Which three bandwidth requirements are used to calculate per client bandwidth through an 802.11n AP network? (Choose three.)
A. 450 Mbps throughput is the client max for 5-GHz radio.
B. CleanAir helps clear noise for 802.11n channel bonding to work.
C. Channel bonding on 5 GHz is required for a client to have a 300 Mbps WiFi link.
D. 300 Mbps throughput is the client max for 2.4-GHz radio.
E. 100 Mbps Ethernet switch port is a potential bottleneck.
F. The remaining bandwidth is divided per device when more clients are connected to one AP.
Answer: A,D,E


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