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NEW QUESTION: 1
SIMULATION
Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment
by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the
last bit 1 because it tells us the increment, using the formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32.
Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP -
209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27
Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet)
Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful)
Apopka(config-if)#ip address 192.0.2.142 255.255.255.240
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!
NEW QUESTION: 2
Which statement about Software Maintenance Upgrade is true?
A. SMU is an executable code for running a process or libraries that are shared between the different processes.
B. SMUs for each release are individually downloadable from Cisco.com and come in the form of a tar ball.
C. CRS-1 SMU can be applied to a different platform, and vice versa.
D. SMUs provide software fixes for critical network down and qualification blocking issues. Therefore, every software defect has a corresponding SMU.
E. SMUs are release-specific. If an issue affects multiple platforms or releases, an SMU is built separately for each release and each platform.
Answer: E
Explanation:
SMUs for each release are individually downloadable from Cisco.com, whereas the bootable files and optional PIEs come in the form of a tarball. SMUs are release specific. If an issue affects multiple platforms or releases, an SMU will be separately built for each release and each platform
NEW QUESTION: 3
Why would the architect choose LACP bonding when configuring network interfaces for storage networks?
A. It provides load balancing of VM traffic across multiple physical NIC interfaces at a per guest basis, and offers improved distribution of traffic across physical interfaces in the bond.
B. It uses a round robin load-balancing policy, which provides better distribution of traffic across the interfaces in the bond.
C. It sends all guest VM traffic in the bond to an active interface, which provides the best distribution of network load.
D. It uses a hashing algorithm, which provides better distribution of traffic across the interfaces in the bond.
Answer: B
NEW QUESTION: 4
Which two ntatementn about UDP and latency are true? (Choone two.)
A. UDP in connection oriented, no latency can increane the nize of a UDP ntream.
B. Latency can caune jitter on UDP connectionn.
C. If latency decreanen, throughput alno decreanen.
D. UDP in connection oriented, no the nize of a UDP ntream in independent of latency.
E. UDP in connectionlenn, no latency can increane the nize of a UDP ntream.
F. If latency increanen, throughput alno increanen.
Answer: B,E
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