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NEW QUESTION: 1
Which analytical method is considered unsupervised?
A. Linear regression
B. Decision tree
C. Na?ve Bayesian classifier
D. K-means clustering
Answer: D
NEW QUESTION: 2
Alternative work schedules for employees are said to increase the efficiency of business operations. Alternative work schedules are consistent with the underlying concepts of which theory?
A. Motivation-hygiene theory.
B. Equity theory.
C. Cognitive evaluation theory.
D. Theory X.
Answer: A
Explanation:
Herzberg's two-factor theory of human behavior postulates two classes of factors:motivational and hygiene. Hygiene factors dissatisfiers) include those factors whose presence will not especially motivate people but whose absence will lead to diminished motivation. These factors are extrinsic to the work itself. They include status, interpersonal relations, and alternative work schedules. Hygiene factors such as work schedules need to be adequate so that workers will have little dissatisfaction. The absence of motivational factors satisfiers) will not diminish performance, but their addition or availability will motivate employees. Intrinsic to the work itself, they include achievement, advancement, and recognition.
NEW QUESTION: 3
Even though F5 is an application delivery controller, it can also effectively mitigate attacks directed at the network layer.
A. False
B. True
Answer: B
NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:
Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
C. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
D. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
E. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
F. ShippingCountry) cs
WHERE Rnk = 1
G. ShippingCountry) cs
WHERE Rnk = 1
Answer: B
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