(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5 PDF updated on Aug 30,2020 contains actual 5)/15!5! = 0.0148 P(16) = 20!(0.5 exam questions and answers with (n-r)]/r!
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(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5
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NEW QUESTION: 1
Common stock and preferred stock differ in that:
A. preferred stockholders have more voting rights than the common stockholders of the firm.
B. the firm is legally mandated to make the dividend payments on its preferred stock; there is no legal
obligation to make dividend payments on its common stock.
C. preferred stockholders will receive their part of the proceeds if the firm is liquidated before the common
shareholders receive anything.
D. common stock pays a fixed dividend while the dividend associated with preferred stock will typically
increase as the earnings of the firm increases.
Answer: C
Explanation:
Common stock and preferred stock differ in that preferred stockholders will receive their part
of the proceeds if the firm is liquidated before the common shareholders receive anything. Neither
preferred stock nor common stock dividends are legal obligations of the firm. Preferred stock typically
pays a fixed dividend that does not vary with the firm's earnings, while the common stock dividend may.
Except in special circumstances specified in the preferred stock agreement, preferred shareholders have
no voting rights.

NEW QUESTION: 2
The sponsors of a well-known charity came up with a unique idea to attract wealthy patrons to the $500 a plate dinner. After the dinner, it was announced that each patron attending could buy a set of 20 tickets for the gaming tables. The chance of winning a prize for each of the 20 plays is 50-50. If you bought a set of
20 tickets, what is the chance that you will win 15 or more prizes?
A. 0.021
B. 0.750
C. 0.250
D. 0.006
E. None of these answers
Answer: A
Explanation:
Explanation/Reference:
Explanation:
This is a binomial probability. The probability of getting r successes out of n trials where the probability of success each trial is p and probability of failure each trial is q (where q = 1-p) is given by: n!(p

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(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5
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(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5
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(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5
Keep walking if all you want is free 5)/15!5! = 0.0148 P(16) = 20!(0.5 (n-r)]/r!
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(n-r)!. Here n = 20, p = 0.5 and q = 0.5 and r = 15,16,17,18,19,20. Therefore we have P(15) = 20!(0.5
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