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NEW QUESTION: 1
A customer has a version 6 2 Integrity VM, and they convert this guest to a vPar using the following command:
The hpvmmodify command completes successfully. When they attempt to boot the guest in vPar mode, they get the following output
What ate the possible reasons the vPar failed to boot? (Select two)
A. The VM guest did not have the required vPar guest kit installed and therefore cannot run in vPar mode
B. TheVM guest was running a version of HP-UX 1li v3 prior 10 the September 2011 update release, which is not a supported vPar OS
C. The VM guest was not configured with sufficient memory to run as a vPar guest
D. The VM guest was running a version of HP-UX 11i v3 prior to the September 2012 update release, which is not a supported vPar OS
E. The VM guest was running HP-UX 11i v2 which is not a supported vPar OS
Answer: B,C
NEW QUESTION: 2
A company hosts an application on multiple Amazon EC2 instances The application processes messages from an Amazon SQS queue writes to an Amazon RDS table and deletes the message from the queue Occasional duplicate records are found in the RDS table The SQS queue does not contain any duplicate messages
What should a solutions archived do to ensure messages are being processed once only?
A. Use the ChangeMessageVisibility API call to increase the visibility timeout
B. Use the ReceiveMessage API call to set an appropriate wait time.
C. Use the CreateQueue API call to create a new queue
D. Use the AddPermission API call to add appropriate permissions
Answer: A
NEW QUESTION: 3
あなたは、Microsoft SQL Server 2012サーバーで主催されるアプリケーションのためのデータベース開発者です。データベースには、次の定義を持つ2つのテーブルが含まれています。
グローバルな顧客には、いくつかの国からの注文を配置します。各々の顧客が最多の注文を出した国を表示する必要があります。 どのTransact-SQLクエリを使用すべきですか。
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
Answer: C
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