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Exam Code: 2V0-21.20
Exam Name: Professional VMware vSphere 7.x
Vendor: VMware

60 Questions & Answers
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NEW QUESTION: 1
Which encryption algorithm is BEST suited for communication with handheld wireless devices?
A. SHA
B. RC4
C. ECC (Elliptic Curve Cryptosystem)
D. RSA
Answer: C
Explanation:
As it provides much of the same functionality that RSA provides: digital signatures,
secure key distribution,and encryption. One differing factor is ECC's efficiency. ECC is more
efficient that RSA and any other asymmetric algorithm.
The following answers are incorrect because :
RSA is incorrect as it is less efficient than ECC to be used in handheld devices.
SHA is also incorrect as it is a hashing algorithm.
RC4 is also incorrect as it is a symmetric algorithm.
Reference : Shon Harris AIO v3 , Chapter-8 : Cryptography , Page : 631 , 638.

NEW QUESTION: 2
Sie haben eine Ansicht mit dem Namen Person.vAdditionalContactInfo, die Daten aus einer Tabelle mit dem Namen Customers verwendet. Die Customers-Tabelle wurde durch Ausführen der folgenden Transact-SQL-Anweisung erstellt:

Sie müssen eine Abfrage erstellen, die den Vor- und Nachnamen eines Kunden aus der Ansicht zurückgibt. Wenn für die Spalte "Kunden-ID" kein Wert definiert ist, muss dem Abfrageergebnis die folgende Meldung hinzugefügt werden: "Kunden-ID existiert nicht." Erstellen Sie die Abfrage anhand der folgenden Richtlinien:
* Verwenden Sie keine Aliase für Spalten- oder Tabellennamen.
* Zeigen Sie die Spalten in derselben Reihenfolge an, wie sie in der Kundentabelle definiert sind.
Ein Teil des korrekten Transact-SQL wurde im Antwortbereich unten bereitgestellt. Geben Sie den Code in den Antwortbereich ein, der das Problem löst und die angegebenen Ziele oder Anforderungen erfüllt. Sie können Code innerhalb des bereitgestellten Codes sowie darunter hinzufügen.


Verwenden Sie die Schaltfläche 'Syntax prüfen', um Ihre Arbeit zu überprüfen. Alle Syntax- oder Rechtschreibfehler werden nach Zeilen- und Zeichenposition gemeldet.
A. 1 SELECT Vorname, Nachname, Kunden-ID =
2 FALL
3 WENN CustomerID NULL IST, DANN "Customer ID existiert nicht"
4 SONST Kunden-ID
5 ENDE
6 FROM Person.vAdditionalContactInfo;
7
In Zeile 1 hinzufügen: CustomerID =
In Zeile 5 hinzufügen: ENDE
B. 1 SELECT Vorname, Nachname, Kunden-ID =
2 FALL
3 WENN CustomerID NULL IST, DANN "Customer ID existiert nicht"
4 SONST Kunden-ID
5 ENDE
6 FROM Person.vAdditionalContactInfo;
7
In Zeile 1 hinzufügen: CustomerID =
In Zeile 5 hinzufügen: ENDE
Answer: B
Explanation:
References:
https://technet.microsoft.com/en-us/library/ms181765(v=sql.105).aspx
https://docs.microsoft.com/en-us/sql/t-sql/queries/is-null-transact-sql

NEW QUESTION: 3
Zoe is the business analyst for her organization. She is currently prioritizing the requirements based on the implementation difficulty of the requirements to help with the solution planning.
Which of the following best describes the approach Zoe is taking with requirements prioritization?
A. The requirements are ranked most difficult to easiest to implement.
B. The requirements are categorized by the likelihood of management approving the requirements.
C. The requirements are categorized by type of work, and then ranked within each category of ease of implementation to difficulty of implementation.
D. The requirements are ranked from easiest to hardest to implement.
Answer: D

NEW QUESTION: 4
Company ABC is deploying Mobile and Remote Access (MRA) to allow employees to login Jabber clients from anywhere on the internet. What is the first DNS query a Jabber client attempts to resolve from the outside of the corporate network?
A. DNS A record _cisco-uds._tcp.abc.com
B. DNS SRV record for _collab-edge._tls.abc.com
C. DNS A record for the Expressway-E FQDN
D. DNS A record for _collab.edge._tls.abc.com
E. DNS SRV record for _cisco-uds._tcp.abc.com
F. DNS SRV record for _cuplogin._tcp.abc.com
Answer: E


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