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NEW QUESTION: 1
A. Option A
B. Option B
C. Option D
D. Option C
E. Option E
Answer: C,D,E
Explanation:
Reference:http://www.vmware.com/files/pdf/techpaper/VMW_Netioc_BestPractices.pdf(page 4)
NEW QUESTION: 2
You have a CSV file that contains user complaints. The file contains a column named Logged.
Logged contains the date and time each compliant occurred. The data in Logged is in the following format: 2018-12-31 at 08:59.
You need to be able to analyze the complaints by the logged date and use a built-in date hierarchy.
What should you do?
A. Change the data type of the Logged column to Date.
B. Create a column by example that starts with 2018-12-31 and set the data type of the new column to Date.
C. Apply a transform to extract the first 11 characters of the Logged column.
D. Apply a transform to extract the last 11 characters of the Logged column and set the data type of the new column to Date.
Answer: B
Explanation:
Option A: Wrong. There is an '' at '' which makes it impossible.
Option B: Wrong. The LAST 11 cannot get the date info.
Option D: Wrong. You can get the right date, but without '' set it as date '', you will not get built-in date Hierarchy which is required.
NEW QUESTION: 3
Microsoft 365 Enterpriseサブスクリプションがあります。
次の展示に示すように、パスワードポリシーを作成します。
ドロップダウンメニューを使用して、図に示されている情報に基づいて各ステートメントを完成させる回答の選択肢を選択します。
注：それぞれの正しい選択には1ポイントの価値があります。
Answer:
Explanation:
Explanation
By default, smart lockout locks the account from sign-in attempts for one minute after 10 failed attempts. In this question, the lockout threshold if 5 failed attempts. The account locks again after each subsequent failed sign-in attempt, for one minute at first and longer in subsequent attempts.
Password evaluation goes through several steps including normalization and Substring matching which is used on the normalized password to check for the user's first and last name as well as the tenant name.
The next step is to identify all instances of banned passwords in the user's normalized new password. Then:
* Each banned password that is found in a user's password is given one point.
* Each remaining unique character is given one point.
* A password must be at least five (5) points for it to be accepted.
Conto$01Pa$$word contains two banned passwords and no remaining unique characters so is given a score of
2 points. This is less than the required 5 points so will be rejected.
Pa$$w0rd contains a banned password and no remaining unique characters so is given a score of 1 point. This is less than the required 5 points so will be rejected.
AzureAD!!111 contains a banned password (AzureAD!!) and has three remaining characters. However, the remaining characters are all the same (they're all 1s) so that is only one unique character. So that password will be given a score of 2. One for the banned password and 1 for the unique character. This is less than the required 5 points so will be rejected.
Password11 does not contain a banned password. Password11 contains 10 characters. However, there are two
's' and two '1' so there are 8 unique characters. Therefore, the password will be given a score of 8 points. This is more than the required 5 points so the password will be accepted.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/authentication/concept-password-ban-bad
https://docs.microsoft.com/en-us/azure/active-directory/authentication/howto-password-smart-lockout
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