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Exam Code: 1z0-1087-23
Exam Name: Oracle Account Reconciliation 2023 Implementation Professional
Vendor: Oracle

60 Questions & Answers
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NEW QUESTION: 1
In Money laundering, a transaction involving cash used to buy high value goods,property or business assets is an example of which stage?
A. Layering
B. Confirmation
C. Placement
D. Integration
Answer: C

NEW QUESTION: 2
An engineer is designing a multi cluster bgp network, each cluster has 2 RRs and 4 RR clients which 2 options must be considered?
A. Clients must not peer with IBGP speakers outside the client router
B. Clients should peer with at least one other client outside it's cluster
C. All RRs must be non client peers in a fully meshed topology
D. All route reflectors should be non client peers & topology partially meshed
Answer: A,B

NEW QUESTION: 3
Select the statement that best describes an Edit Validate rule. (Choose One)
A. Used to test property values against specific conditions
B. Used to ensure a required relationship between two properties
C. Used to limit the input to a specified number of characters
D. Used to test input values against a specific pattern
Answer: D

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2. Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
B. SELECT StudentCode as Code, DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
E. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
G. SELECT StudentCode as Code, RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
H. SELECT Id, Name, Marks, DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank FROM StudentMarks
Answer: E


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